TS ICET 23 May 2019 Shift 1 Paper

Question : 148 of 200

Marks: +1, -0

If a number is selected at random out of the first 120 natural numbers, then the probability that it is divisible by 5 or 8 is

Solution:

P (A U B) = P(A) + P (B) – P (A ∩ B)

=\;{24}/{120}+\;{15}/{120}-\;{3}/{120}=\;{36}/{120}=\;{3}/{10}

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