TS ICET 23 May 2019 Shift 1 Paper

Question : 144 of 200

Marks: +1, -0

If the standard deviation of 5, 7, 9, .... 151 is

Solution:

SD (32, 44, 56, ……….. 908)
=SD

(6 × 5+2,6 × 7+2,6 × 9+2 . . . .6 × 151+1

=6\SD (5,7,9, . . . . . . 151)

=6 σ

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