TS ICET 23 May 2018 Shift 2 Paper

Question : 144 of 200

Marks: +1, -0

The standard deviation of any five consecutive positive integers is

Solution:

Standard deviation of n observations which are in arithmetic progression is (common difference × √{\;{n^{2}-1}/{12}}

=1√{\;{5^{2}-1}/{12}}=√{2} .( c.d. =1, n =5)

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