TS ICET 23 May 2018 Shift 1 Paper

Question : 83 of 200

Marks: +1, -0

The number of positive divisors of 37800 is?

Solution:

37800 = 2^3 × 3^3 × 5^2 × 7^1

The number of positive divisors of 37800

= (3 + 1) × (3 + 1) × (2 + 1) × (1 + 1)

=4×4×3×2 = 96

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