TS ICET 23 May 2018 Shift 1 Paper

Question : 141 of 200

Marks: +1, -0

If the arithmetic mean of

17,2a-b,2b-c

and

2c-a

is 20 then the arithmetic mean of a. b, c is

Solution:

GIven

\;{17+2 a-b+2 b-c+2 c-a}/{4}=20

⇒a + b + c = 4 × 20 – 17 = 63

AM of a,b and c

={a+b+c}/3=63/3=21

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