TS ICET 23 May 2018 Shift 1 Paper

Question : 129 of 200

Marks: +1, -0

If the sum of the first three terms of a geometric progression is

39/10

and if their product is 1. Then common ratio is

Solution:

Let the three terms in GP be a, ar and

ar^2

Given.

a×ar×ar^2 = 1

⇒(ar)^3=1⇒ar=1

a=1/r

Given

a+ar+ar^2=39/10

⇒1/r+1+r=39/10

⇒r+1/r=29/10

⇒r=2/5

5/2

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