\sqrt{(\ab-\ac-\bc)^2+ 4\abc(\a+\b)}

TS ICET 23 May 2018 Shift 1 Paper

Question : 122 of 200

Marks: +1, -0

√{(\ab-\ac-\bc)^2+ 4\abc(\a+\b)}

Solution:

Let ab = A and c(a+b)=B

√{(a b-a c-b c)^{2}+4 a b c(a+b)}

=√{(A-B)^{2}+4 A B}=√{(A+B)^{2}}= A + B

ab + c(a+b) = ab + ac + bc

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