The domain of the function fix) = 1/{x^2+1} is

TS ICET 23 May 2018 Shift 1 Paper

Question : 115 of 200

Marks: +1, -0

The domain of the function fix) =

1/{x^2+1}

Solution:

f(x)=1/{x^2+1}

;Since

x^2+1≠0

the denominator can never be equal to zero and hence f(x) is defined for all values of x.
Domain of f(x) = R

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