TS ICET 23 May 2018 Shift 1 Paper

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Question : 113 of 200

Marks: +1, -0

If f(x) =

x/√{1-x^2}

and g(x) =

x/√{1+x^2}

then (f o g)x =

$√{{1-x^2}/{1+x^2}}$
$√{{1+x^2}/{1-x^2}}$
$x^2$
x

Solution:

f(x) =

x/√{1-x^2}

and g(x) =

x/√{1+x^2}

fog(x)=f(g(x))={({x}/{√{1+x^{2}}})}/{√{1-({x}/{√{1+x^{2}}})^{2}}}={({x}/{√{1+x^{2}}})}/{√{1-({x^{2}}/{1+x^{2}})}}=x

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