TS ICET 23 May 2018 Shift 1 Paper

Triangle having angles 30°,60° and 90° have their sides in ratio $1:\sqrt{3}:2.$
Given the smallest side of the triangle (b) = 9.
⇒Height of the triangle (h) $=9\sqrt{3}$ and the hypotenuse = 18
Area of the right-angled triangle$=\frac{1}{2}\mathit{b}\mathit{h}$
$=\frac{1}{2}\left(9\right)\left(9\sqrt{3}\right)=\frac{81}{2}\sqrt{3}$