TS ICET 2016 Question Paper with Solutions for online practice

Note : In a code the

n^{th}

letter in the English alphabet is coded as the

r^{th}

letter of it, where r is the remainder when 3n + 2 is divided by 26. For example, the 7th letter G is coded as W since 3.7 + 2 = 23 and W is the 23rd letter; the 8th letter H is coded as Z since 3.8 + 2 = 26 and Z is the 26th letter in the alphabet. The reverse process is used for decoding. Based on this coding and decoding answer Q. Nos. 56 to 60.

Question : 76 of 200

Marks: +1, -0

The cost price of 10 articles is equal to the sale price of 12 of the same articles. Then the outcome of the transaction is

16 $2/3$ % gain
16 $2/3$ % loss
8 $2/3$ % gain
8 $2/3$ % loss/Ibojo

Validate

Solution:

LCM (10,12) = 60.
Let 60 k = C.P. of 10 articles = S.P. of 12 articles.
∴ C.P. of 1 article = 6k.
S.P. of 1 article = 5k.

∴ % loss

=\;\;{6k-5k}/{6k}×100=\;\;{100}/{6}\%=16\;\;{2}/{3}\%

loss

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