If a ⊙ b = \sqrt{ab}+1/\sqrt{ab} and a Δ b = \sqrt{ab}-1/\sqrt{ab}, then \frac{4⊙9+4\\Delta9}{4⊙9-4\\Delta9}

TS ICET 2015 Question Paper with Solutions for online practice

The letters in the English alphabet are coded in the reverse order. For example, A is coded as Z, B is Coded as Y,....

Following this code answer the questions from 56 to 60.

Question : 66 of 200

Marks: +1, -0

If a ⊙ b =

√{ab}+1/√{ab}

and a Δ b =

√{ab}-1/√{ab}

, then

{4⊙9+4\Δ9}/{4⊙9-4\Δ9}

$1/36$
$1/18$
18
36

Validate

Solution:

Given:a ⊙ b =

√{ab}+1/√{ab}

and a Δ b =

√{ab}-1/√{ab}

∴4⊙9=√{4+9}+1/√{4+9}=6+1/6=37/6

4∆9=√{4+9}-1/√{4+9}=6-1/6=35/6

∴{4⊙9+4∆9}/{4⊙9-4∆9}={37/6+35/6}/{37/6-35/6}=36

Aliter :

{a⊙b+a∆b}/{a⊙b-a∆b}={2√{ab}}/(2/√{ab})=ab

∴{4⊙9+4∆9}/{4⊙9-4∆9}=4×9=36

Go to Question:

Prev Question

Next Question