TS ICET 2015 Question Paper with Solutions for online practice

Question : 127 of 200

Marks: +1, -0

In ΔABC, ∠ABC = 45°, ∠CAB = 30° and CD is perpendicular to AB. If CD = 100, then AB =

Solution:

Given : ∠ABC = 45°, ∠CAB = 30°,
CD ⊥ AB, CD = 100
In ΔADC,

AD=CD\cot30°=100√3

In ΔBDC,
BD = CD = 100 [ ∠CBD = 45° and CD ⊥ BD]

∴\AB=\AD+\BD=100√3+100=100(√3+1)

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