(\frac{\sin45^\circ+\cos45^\circ+\tan45^\circ}{\sin45^\circ-\cos45^\circ-\tan45^\circ})^2 =

TS ICET 2015 Question Paper with Solutions for online practice

Question : 125 of 200

Marks: +1, -0

({\sin45°+\cos45°+\tan45°}/{\sin45°-\cos45°-\tan45°})^2

Solution:

Given :

({\sin45°+\cos45°+\tan45°}/{\sin45°-\cos45°-\tan45°})^2

({1/√2+1/√2+1}/{1/√2-1/√2-1})=({√2+1}/{-1})^2

=1+2+2√2=3+2√2

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