TS ICET 19 Aug 2021 Shift 1 Paper

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Question : 137 of 200

Marks: +1, -0

{ABCD}

is a trapezium with

{AB}

and

{CD}

as its parallel sides. If the diagonals

{AC}

and

{BD}

intersect in

{E}

and

{CE}: {EA}=3: 2

, then

{AB}: {CD}=

$1: 2$
$2: 3$
$3: 4$
$4: 5$

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