A magnetic dipole of moment m^{\to} is placed in the magnetic field B^{\to}. It is free to rotate about an axis about which its moment of inertia is I. It is displaced by a small angle \theta_0(\theta_0 ≪ 1) at time t - Os and released. The dipole undergoes simple harmonic motion with angular frequency ox Its potential energy at time t is: (Assume sin (α) ~ α cos(α) = 1 - \alpha^2/2 if α ≪ 1)

Correct Answer is : −mB(1−θ022cos2(ωt))

- mB (1-\theta_0^2/2 \cos^2 (\omegat))

- mB (1-\theta_0^2/2 \sin^2 (\omegat))

- mB (1-\theta_0^2/2) \cos^2 (\omegat)

- mB (1-\theta_0^2/2) \sin^2 (\omegat)

TS EAMCET Medical 8 May 2019 Shift 2 Paper

Question : 111 of 159

Marks: +1, -0

A magnetic dipole of moment

→

is placed in the magnetic field

→

. It is free to rotate about an axis about which its moment of inertia is I. It is displaced by a small angle θ0(θ0≪1) at time t - Os and released. The dipole undergoes simple harmonic motion with angular frequency ox Its potential energy at time t is: (Assume sin (α) ~ α cos(α) = 1 -

α2

if α ≪ 1)

−mB(1−
θ02
2
cos2(ωt))
−mB(1−
θ02
2
sin2(ωt))
−mB(1−
θ02
2
)cos2(ωt)
−mB(1−
θ02
2
)sin2(ωt)

Validate

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