The electric field in an electromagnetic wave is given by E^{\to} = E_0 e_z^{\^} sin (ky - ωt) where k = k^{\to}.e_y^{\^}. . The magnetic field is then given by (e_x^{\^},e_y^{\^},e_z^{\^} are unit vectors along x, y and z direction and c is the speed of light)

Correct Answer is : →B = +E0c^ex sin (ky - ωt)

B^{\to} = {+E_0}/c (sin (ky - ωt) e^{\^}_x + cos (ky - ωt) e^{\^}_y)

B^{\to} = {+E_0}/c e^{\^}_x sin (ky - ωt)

B^{\to} = {-E_0}/c e^{\^}_z sin (ky - ωt)

B^{\to} = {-E_0}/c e^{\^}_y sin (ky - ωt)

TS EAMCET Medical 8 May 2019 Shift 1 Paper

Question : 114 of 161

Marks: +1, -0

The electric field in an electromagnetic wave is given by

→

= E0

sin (ky - ωt) where k =

→

. . The magnetic field is then given by (

are unit vectors along x, y and z direction and c is the speed of light)

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