A particle of charge \q=1.5 \x \10^{-19} \C and mass \m=9 \x \10^{-31} \Kg follows a helical path in a uniform magnetic field given by \B^{\to}= (20\i^{\^}-50 \j^{\^}+30 \k^{\^}) mT. At time t = 0, the velocity of the particle is given by \V^{\to}= (20\i^{\^}-30 \j^{\^}+50 \k^{\^}) m/s. If R is the radius of helical path then correct statement is

Correct Answer is : 5 < R < 6 nm

TS EAMCET Medical 28 Sept 2020 Shift 2 Paper

Question : 109 of 160

Marks: +1, -0

A particle of charge q=1.5 x 10−19C and mass m=9 x 10−31‌Kg follows a helical path in a uniform magnetic field given by

→

=(20

−50

+30

) mT. At time t = 0, the velocity of the particle is given by

→

=(20

−30

+50

) m/s. If R is the radius of helical path then correct statement is

Go to Question:

Prev Question

Next Question