Vector a^{\to}=i^{\^}+2j^{\^}+2k^{\^} and b^{\to}=i^{\^}-j^{\^}+k^{\^}. What is the unit vector along a^{\to}+b^{\to} ?

Correct Answer is : 2^i+^j+3^k√14

{2i^{\^}+j^{\^}+3k^{\^}}/\sqrt14

{2i^{\^}-j^{\^}+4k^{\^}}/\sqrt20

{2i^{\^}+j^{\^}+3k^{\^}}/\sqrt13

{2i^{\^}+j^{\^}-3k^{\^}}/\sqrt10

TS EAMCET Medical 28 Sept 2020 Shift 1 Paper

Question : 85 of 160

Marks: +1, -0

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