TS EAMCET Medical 2018 May 3 Shift 1Paper
© examsiri.com
Question : 131 of 160
Marks:
+1,
-0
Find out the value of log K [K = equilibrium constant] for the following reaction at 298 K [Given Δ r G° at 298 K = -13.6 kJ m o l − 1 ]
2 N H 3 + C O 2 ( g ) ⇌ N H 2 C O N H 2 ( a q ) + H 2 O ( l )
Go to Question: