A steady current I flows down a long rod of radius 'a' in such a way that its current density J^{\to} = kr^2 r^{\^} , where A'is a positive constant of appropriate dimensions. r^{\^} is the radial distance from the axis and r is the limit vector along the radial direction.Then the magnitude of the magnetic field at any point r (r

Correct Answer is : µ0Ir32πa4

TS EAMCET Medical 2018 May 2 Shift 1 Paper

Question : 109 of 160

Marks: +1, -0

A steady current I flows down a long rod of radius 'a' in such a way that its current density

→

= kr2

, where A'is a positive constant of appropriate dimensions.

is the radial distance from the axis and r is the limit vector along the radial direction.Then the magnitude of the magnetic field at any point r (r < a) inside the rod is

µ0Ir
πa2
µ0Ir2
2πa2
µ0Ia2
πr3
µ0Ir3
2πa4

Validate

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