TS EAMCET Medical 2015 Paper

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Question : 94 of 160

Marks: +1, -0

The position of a particle is given by

→

r

= 3t

^

i

−4t2

^

j

+5

^

k

. Then the magnitude of the velocity of the particle at t = 2 sec is

√276 m/s
√246 m/s
√255 m/s
√265 m/s

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