The rate constant of a first order reaction is 6.4 \times 10^{-5} {\S}^{-1} at 47^{\circ} {\C} and 1.6 \times 10^{-5} {\S}^{-1} at 27^{\circ} {\C}. The activation energy for the reaction is around (\log 4=0.6021, {\R}=8.314 {\JK}^{-1} {\mol}^{-1})

Correct Answer is : 55.0kJmol−1

TS EAMCET Medical 11 May 2023 Shift 2 Paper

Question : 142 of 160

Marks: +1, -0

The rate constant of a first order reaction is 6.4×10−5S−1 at 47∘C and 1.6×10−5S−1 at 27∘C. The activation energy for the reaction is around
(log‌4=0.6021,R=8.314JK−1mol−1)

110.0‌kJ‌mol−1
27.0‌kJ‌mol−1
55.0‌kJ‌mol−1
220.0‌kJ‌mol−1

Validate

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