A clock with a brass pendulum gains 1 minute per day in winter at a temperature of 20^{\circ} {\C}. Another clock with a steel pendulum loses 1 minute per day in summer at a temperature of 40^{\circ} {\C}. The temperature at which the two clocks show correct time is (\alpha_{\text{brass }}=18 \times 10^{-6} \/{ }^{\circ} {\C} ; \alpha_{\text{steel }}=12 \times 10^{-6} \/{ }^{\circ} {\C})

TS EAMCET Medical 10 May 2023 Shift 1 Paper

Question : 95 of 160

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A clock with a brass pendulum gains 1 minute per day in winter at a temperature of 20∘C. Another clock with a steel pendulum loses 1 minute per day in summer at a temperature of 40∘C. The temperature at which the two clocks show correct time is (α‌brass ‌=18×10−6∕‌∘C;α‌steel ‌=12×10−6∕‌∘C)

30° C
28° C
27° C
25° C

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