For the reaction {Sn}( {s}) {Sn}^{2+}(0.10 {M}) \/ {Pb}^{2+}(0.5 {M}) {Pb}( {s}), What will be the approximate E_{\text{cell }} when [ {Pb}^{2+}] is 0.1 {M} ( given E_{S_{n}^{2+} \/ S_{a}}^{0}=-0.136 {V}: E_{ {p}_{b^{2}+} \/ P_{b}}^{0}=-0.126 {V})

TS EAMCET Medical 10 AUG 2021 Shift 1 Paper

Question : 145 of 160

Marks: +1, -0

For the reaction Sn(s)Sn2+(0.10M)∕Pb2+(0.5M)Pb(s), What will be the approximate E‌cell ‌ when [Pb2+] is 0.1M
( given ESn2+∕Sa0=−0.136V:Epb2+∕Pb0=−0.126V)

−0.011V
−0.022V
−0.03V
+0.022V

Validate

Go to Question:

Prev Question

Next Question