A plane electromagnetic wave of frequency 10 {MHz} travels in free space in X-Y plane making an angle of 45^{\circ} with +x - axis. At a particular point in space and time, \overrightarrow{ {E}=6 \hat{ {k} {V} \/ {m}. What is \overrightarrow{ {B} at this point?

Correct Answer is : √2×10−8(∧i−∧j)T

\sqrt{2} \times 10^{-8}(\hat{i}-\hat{j}) T

2 \times 10^{-8}(\hat{ {i}-\hat{ {j}) {T}

2 \times 10^{-8}(\hat{ {i}+\hat{ {j}) {T}

\sqrt{2} \times 10^{-8}(\hat{i}+\hat{j}) T

TS EAMCET Medical 09 AUG 2021 Shift 1 Paper

Question : 114 of 160

Marks: +1, -0

A plane electromagnetic wave of frequency 10MHz travels in free space in X−Y plane making an angle of 45∘ with +x - axis. At a particular point in space and time,

→

∧

V∕m. What is

→

at this point?

√2×10−8(
∧
i
−
∧
j
)T
2×10−8(
∧
i
−
∧
j
)‌T
2×10−8(
∧
i
+
∧
j
)‌T
√2×10−8(
∧
i
+
∧
j
)T

Validate

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