\int {\tan x}/{ \sec ^2 x (1+ \sec ^6 x) ^{\frac{2}{3}}} \dx= [TG EAPCET 14 May 2023 Shift 2]

Correct Answer is : −12(1+cos6x)13+c

\frac{-1}{2} (1+ \sec ^6 x) ^{\frac{1}{3}}+ {\c}

2 (1+ \sec ^6 x) ^{\frac{4}{3}}+c

\frac{-1}{2} (1+\cos ^6 x) ^{\frac{1}{3}}+c

2 (1+\cos ^6 x) ^{\frac{1}{3}}+c

TS EAMCET Engineering 14 May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 70 of 160

Marks: +1, -0

∫‌

tan‌x

sec2x(1+ sec6x)‌

‌dx=

[TG EAPCET 14 May 2023 Shift 2]

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