TS EAMCET Engineering 13 May 2023 Shift 2 Solved Paper

When the origin is shifted to the point (h,k) by translating the coordinate axes, the equation S≡2x2−xy+y2+2x+3y+1=0 is changed to S′≡ax2+2hxy+by2−3=0. Again by rotating the coordinate axes about the new origin through the angle θ in the positive direction, S′=0 is changed to Ax2+By2+C=0. Then h+k+tan‌2‌θ=