\cos \frac{\pi}{7} \cos \frac{2 \pi}{7} \cos \frac{3 \pi}{7} \cos \frac{\pi}{14} \cos \frac{3 \pi}{14} \cos \frac{5 \pi}{14}= [TG EAPCET 13 May 2023 Shift 2]

Correct Answer is : 132[sin2π7+sin3π7−sinπ7]

\frac{1}{16} [ \sin \frac{\pi}{7}+ \sin \frac{2 \pi}{7}+ \sin \frac{3 \pi}{7}]

\frac{1}{8} [ \sin \frac{2 \pi}{7}+ \sin \frac{3 \pi}{7}- \sin \frac{\pi}{7}]

\frac{1}{32} [ \sin \frac{2 \pi}{7}+ \sin \frac{3 \pi}{7}- \sin \frac{\pi}{7}]

\frac{1}{32} [ \sin \frac{\pi}{7}- \sin \frac{2 \pi}{7}+ \sin \frac{3 \pi}{7}]

TS EAMCET Engineering 13 May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 27 of 160

Marks: +1, -0

cos‌

‌cos‌

2π

‌cos‌

3π

‌cos‌

3π

‌cos‌

5π

[TG EAPCET 13 May 2023 Shift 2]

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