\int \frac{1}{16-7 \sin ^2 x} \dx= [TG EAPCET 13 May 2023 Shift 1]

Correct Answer is : 112Tan−1(3tanx4)+c

\frac{1}{12} {\Tan}^{-1} (\frac{3 \tan x}{4}) + {\c}

\frac{1}{3} {\Sin}^{-1} (\frac{3 \sin x}{4}) + {\c}

\frac{1}{12} \log ( {4-\sqrt{7} \sin x}/{4+\sqrt{7} \sin x}) +c

\frac{1}{12} \log ( {4+\sqrt{7} \sin x}/{4-\sqrt{7} \sin x}) +c

TS EAMCET Engineering 13 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 70 of 160

Marks: +1, -0

∫‌

16−7sin‌2x

‌dx=

[TG EAPCET 13 May 2023 Shift 1]

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