If A=\left[\begin{array}{ccc}k & 5 & 2 \ 2 & -k & 5 \ 5 & 2 & -k]\end{array} and {\det} A=190 then {\Adj} A= [TG EAPCET 13 May 2023 Shift 1]

Correct Answer is : [−1193131−19−111919−19]

\left[\begin{array}{ccc}-1 & 19 & 31 \ 31 & -19 & -11 \ 19 & 19 & -19]\end{array}

\left[\begin{array}{ccc}-1 & 31 & 19 \ 19 & -19 & 19 \ 31 & -11 & -19]\end{array}

\left[\begin{array}{ccc}-1 & 19 & 31 \ -31 & -19 & -11 \ 19 & 19 & -19]\end{array}

\left[\begin{array}{ccc}-1 & -31 & 19 \ 19 & -19 & 19 \ 31 & -11 & -19]\end{array}

TS EAMCET Engineering 13 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 6 of 160

Marks: +1, -0

If A=[

] and det‌A=190 then Adj‌A=

[TG EAPCET 13 May 2023 Shift 1]

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