If ' i ' is the root of the equation {\x}^2+1=0 then (1+\sqrt{3} i)^{2023}+(1-\sqrt{3} i)^{2023}= [TG EAPCET 13 May 2023 Shift 1]

TS EAMCET Engineering 13 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 11 of 160

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If ' i ' is the root of the equation x2+1=0 then (1+√3i)2023+(1−√3i)2023=

[TG EAPCET 13 May 2023 Shift 1]

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