TS EAMCET Engineering 12 May 2023 Shift 2 Solved Paper

Section: Mathematics

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Question : 80 of 160

Marks: +1, -0

The general solution of the differential equation (2x−10y3)dy+y‌dx=0,y≠0 is

[TG EAPCET 12 May 2023 Shift 2]

x2y−2y3=c
xy2−2y5=c
xy3+2y=c
xy2+3y=c

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