The equation of the straight line passing through the point (3,2) and inclined at an angle of 60^{\circ} with the line \sqrt{3} x+y=1 is [TG EAPCET 12 May 2023 Shift 2]

Correct Answer is : √3x−y+(2−3√3)=0

TS EAMCET Engineering 12 May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 45 of 160

Marks: +1, -0

The equation of the straight line passing through the point (3,2) and inclined at an angle of 60∘ with the line √3x+y=1 is

[TG EAPCET 12 May 2023 Shift 2]

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