TS EAMCET Engineering 12 May 2023 Shift 1 Solved Paper

Section: Mathematics

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Question : 75 of 160

Marks: +1, -0

The general solution of ‌

dy

dx

+yf′(x)−f(x)f′(x)=0,‌‌y≠f(x) is

[TG EAPCET 12 May 2023 Shift 1]

y=f(x)+1+ce−f(x)
y=ce−f(x)
y=f(x)−1+ce−f(x)
y=f(x)+cef(x)

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