The electric potential at a place is varying as V=\frac{1}{2} (y^2-4 x) volt. Then the electric field at x=1 m and y=1 m is [TG EAPCET 12 May 2023 Shift 1]

Correct Answer is : 2^i−^jVm−1

2 \stackrel{\^}{i}+\stackrel{\^}{j} V^{-1}

-2 \stackrel{\^}{ {\i}}+\stackrel{\^}{ {\j}} {\Vm}^{-1}

2 \stackrel{\^}{i}-\stackrel{\^}{j} {\Vm}^{-1}

-2 \stackrel{\^}{ {\i}}+2 \stackrel{\^}{ {\j}} {\Vm}^{-1}

TS EAMCET Engineering 12 May 2023 Shift 1 Solved Paper

Section: Physics

Question : 104 of 160

Marks: +1, -0

The electric potential at a place is varying as V=‌

(y2−4x) volt. Then the electric field at x=1m and y=1m is

[TG EAPCET 12 May 2023 Shift 1]

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