TS EAMCET 9-Sep-2020 Shift 2 Solved Paper

The motion of ball is as shown below At bottom of incline (at P ) the potential energy of ball is converted into kinetic energy i.e..
‌

1

2

mv2=mgh
⇒‌‌v=√2gh .....(i)
To complete the vertical circle, the velocity of ball should be at least √5gR.
⇒‌‌v≥√5gR
√2gh≥√5gR [From Eq. (i)]
⇒‌‌h≥‌

5

2

R or hmin=‌

5

2

×20=50cm