\E_1 and \E_2 are two independent events of a random experiment with \P(\E_1)=1/2 and \P(\E_1\cup\E_2)=2/3. Then match the items of List - 1 with those of List - II \table \List-\I, \List-\II;{\A)}P(E_2)=,{\I)}2/3;{\B)}P(E_1{|}E_2)=,{\II)}5/6;{\C)}P(E_2^{-}{|}E_1)=,{\III)}1/3;{\D)}P(E_1^{-}\cupE_2^{-})=,{\IV)}1/2;,{\V)}1/6

Correct Answer is : ABCDIIIIVIII

\table \A,\B,\C,\D;\III,\II,\I,\IV

\table \A,\B,\C,\D;\III,\IV,\I,\II

\table \A,\B,\C,\D;\III,\IV,\II,\I

\table \A,\B,\C,\D;\IV,\III,\I,\II

TS EAMCET 9-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

Question : 38 of 160

Marks: +1, -0

E1 and E2 are two independent events of a random experiment with P(E1)=

and P(E1∪E2)=

. Then match the items of List - 1 with those of List - II

List−I

List−II

A)‌P(E2)=

I)‌

B)‌P(E1|E2)=

II)‌

C)‌P(

−

|E1)=

III)‌

D)‌P(

−

∪

−

IV)‌

‌

V)‌

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A	B	C	D
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IV	III	I	II