TS EAMCET 9-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

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Question : 76 of 160

Marks: +1, -0

Lt

n→∞

n

π

r=1

(1+

r2

n2

)

2r

n2

=

log(
4
e
)
log(
2
e
)
2
e
4
e

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