\int{Tan^{-1}x}/x^3dx=

Correct Answer is : −12x−(12+12x2)Tan−1x+C

\frac{-(x^2+1)}{2x}Tan^{-1}x-1/{2x}+C

\frac{-(x^2+1)}{2x^2+1}Tan^{-1}x-1/{2x^2}+C

\frac{-1}{2x}-(1/2+1/{2x^2})Tan^{-1}x+C

TS EAMCET 9-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 71 of 160

Marks: +1, -0

∫

Tan−1x

dx=

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