TS EAMCET 9-Sep-2020 Shift 1 Solved Paper

We have,
S1:x2+y2+2x+8y−23=0
S2:x2+y2−4x+10y+19=0
Now, centres of both the circles are C1(−1,−4) and C2(2,−5)
∴ Pole of C1(−1,−4) with respect to S2 is
⇒‌‌−3x+y+1=0
⇒‌‌3x−y−1=0....(i)
and Pole of C2(2,−5) with respect to S1 is
3x−y−41=0.....(ii)
Eqs. (i) and (ii) shows parallel lines and distance between them =|‌

−41+1

√9+1

|=|‌

−40

√10

|=4√10 units