TS EAMCET 9-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

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Question : 25 of 160

Marks: +1, -0

Sinh−1(−2)+Cosech−1(−2)+Coth−1(−2)=

log(
7−3√5
2√3
)
log(
3−√5
2√3
)
log(
7+3√5
2√3
)
log(
3+√5
2√3
)

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