TS EAMCET 9-Sep-2020 Shift 1 Solved Paper

We have, 10 Red and 5 Yellow roses of different sizes.
Now, x= number of garlands that can be formed with all these flowers so that no two yellow roses come together
=‌

1

2

(10−1)!×‌10P5
=‌

1

2

×9!×‌

10!

5!

=x=‌

10!

2

[‌

9!

5!

]
⇒‌‌‌

2x

10!

=‌

9!

5!

and y= number of garlands formed with all these flowers so that all the red roses coming together
=‌

1

2

(6−1)!×10!=‌

1

2

×5!×10!
⇒‌‌‌

2y

10!

=5!
∴‌‌‌

2(x−y)

10!

=‌

9!

5!

−5!