TS EAMCET 9-Sep-2020 Shift 1 Solved Paper

Maximum velocity of emitted photoelectrons is
vmax=1.6×106ms−1
Maximum kinetic energy of emitted photoelectrons is
Kmax=‌

1

2

mvmax2
=‌

1

2

×9.1×10−31×(1.6×106)2J
=‌

9.1×10−31×(1.6×106)2

2×1.6×10−19

eV
=7.2eV
So, work function = incident energy - maximum kinetic energy of electron
=10.5−7.2=3.3eV