\int \frac{d x}{9 \cos ^2 2 x+16 \sin ^2 2 x}= [TG EAPCET 9 May 2024 Shift 2]

Correct Answer is : 124Tan−1(43tan2x)+c

\frac{1}{25} {\Tan}^{-1} (\frac{3}{4} \sec ^2 2 x) + {\c}

\frac{1}{25} {\Tan}^{-1} (\frac{4}{3} \sec ^2 2 x) + {\c}

\frac{1}{24} {\Tan}^{-1} (\frac{3}{4} \tan 2 x) + {\c}

\frac{1}{24} {\Tan}^{-1} (\frac{4}{3} \tan 2 x) + {\c}

TS EAMCET 9 May 2024 Shift 2 Solved Paper

Section: Mathematics

Question : 74 of 160

Marks: +1, -0

∫‌

9cos22x+16sin‌22x

[TG EAPCET 9 May 2024 Shift 2]

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