TS EAMCET 9 May 2024 Shift 2 Solved Paper

Section: Mathematics

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Question : 5 of 160

Marks: +1, -0

If A=[

1	2	2
3	2	3
1	1	2

] and A−1=[

a11	a12	a13
a21	a22	a23
a31	a32	a33

], then

∑

1≤i≤3

1≤j≤3

aij=

[TG EAPCET 9 May 2024 Shift 2]

‌
2
3
‌
1
3
1
17

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