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Question : 44 of 160
Marks:
+1,
-0
Solution:
Given,
(−2,−1),(2,5) and
(m,n) are three vertices of a triangle whose orthocenter is
(2,‌)Here, line
AH⟂ line
BC and line
CH⟂ line
AB
mAB=‌=‌=‌mAH=‌=‌=‌mBC=‌⇒‌‌mCH=‌=‌⇒‌‌mAH×mBC=−1‌‌‌×‌=−1⇒‌‌mCH×mAB=−1‌‌‌×‌=−1On solving Eqs. (i) and (ii), we get
m=6 and
n=−1∴m+n=6+(−1)=5
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