TS EAMCET 9 May 2024 Shift 2 Solved Paper

Section: Mathematics

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Question : 21 of 160

Marks: +1, -0

If

‌

3x4−2x2+1

(x−2)4

=A+‌

B

x−2

+‌

C

(x−2)2

+‌

D

(x−2)3

+‌

E

(x−2)4

, then 2A+3B−C−D+E=

[TG EAPCET 9 May 2024 Shift 2]

0
1
−11
−39

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