TS EAMCET 9 May 2024 Shift 1 Solved Paper

The relationship between the two scales,
F=‌

9

5

C+32
If the temperature is twice the celsius temperature, we can write
F=2C
Now, ‌

9

5

×C+32=2C
‌‌

9

5

×C+32=‌

10

5

C
‌32=‌

10

5

C−‌

9

5

C⇒32=‌

1

5

C
‌C=160‌‌...‌ (iii) ‌
Fahrenheit temperature,
F‌=‌

9

5

×160+32
F‌=288+32
⇒‌‌F‌=320
Therefore, the temperature on the fahrenheit scale that is twice the temperature of 160∘C on the celsius scale is 320∘F.