TS EAMCET 9 May 2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 80 of 160

Marks: +1, -0

The general solution of the differential equation (3x2−2xy)dy+(y2−2xy)‌dx=0 is

[TG EAPCET 9 May 2024 Shift 1]

‌x2−xy=cy2
‌y2−xy=cx3
‌xy−x2=cy3
‌xy−y2=cy3

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